SOLUTION: Stanbon, you are our hero!! We have an oblique triangle with angle B measuring 46.2 degrees. Side c measures 7.3, side b measures 10.3. The values given for sin(46.2) are 0.7218
Question 181607: Stanbon, you are our hero!! We have an oblique triangle with angle B measuring 46.2 degrees. Side c measures 7.3, side b measures 10.3. The values given for sin(46.2) are 0.7218, and for cos(46.2) is 0.6921. What is the value of sin C? Found 2 solutions by Mathtut, Edwin McCravy:Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website! MATHTUT'S SOLUTION USING METHOD THAT LAW OF SINES WAS DERIVED FROM
ok!!!! we need to construct a line perpendicular to line BC coming from
vertex A .
:
we will call that distance h. This splits the triange into 2 right triangles.
:
sin 46.2=h/7.3
:
h=7.3(.7218)=5.27
:
sin C=5.27/10.3= Answer by Edwin McCravy(20067) (Show Source): You can put this solution on YOUR website! Edwin's solution using the law of sines:
Use the law of sines:
We are only dealing with the last two fractions:
Cross-multiply:
Divide both sides by
Substitute for , for ,
and for and
Now get your calculator,
Edwin