SOLUTION: What would be the solution to these problems? 1.If cos 0= -4/5,find sec 0. 2.Find the value of cot 330. 3.Find the value of sin 0 for angle 0 in standard position of the point (

Algebra.Com
Question 172925: What would be the solution to these problems?
1.If cos 0= -4/5,find sec 0.
2.Find the value of cot 330.
3.Find the value of sin 0 for angle 0 in standard position of the point (-2,-4)that lies on the terminal side.
4.Suppose 0 is an angle in standard position whose terminal side lies in quadrant 2 and the tan 0=-1.Find the remaining trigonometric functions for the function 0.
5.Use the right triangle ABC to find side a if A=37 and b=9

Answer by midwood_trail(310)   (Show Source): You can put this solution on YOUR website!
I will answer number (2) only. We would love to see your effort.
2.Find the value of cot 330.
Well, cot330 lies in quadrant 4.
In quadrant 4, cotagent is negative.
Let's find the reference angle of cot330.
To do so, subtract 330 degrees from 360 degrees.
So, 360 - 330 = 30 degrees
Final answer: cot330 = 30 degrees = sqrt{3} but since cotagent is negative in quadrant 4, we must include the negative sign to get the answer -sqrt{3}

RELATED QUESTIONS

if sec(x) = -5/4 and sin(x) < 0, find the exact value of... (answered by harpazo,lwsshak3)
1. Find the values of the remaining functions if tan=1/4, sin<0 sin= cos= csc= sec=... (answered by MaxWong,MathTherapy)
If sin(x)=-3/5 and cos(x)>0, find the value of... (answered by Alan3354)
i was wondering how you do these problems: The directions are to find the exact value of... (answered by jim_thompson5910)
If sec(theta)=4, and sin(theta)< 0, find the exact value of... (answered by danarusu)
Find the value of sec(theta), if cos(theta)=2/19; 0<=theta<=90. If you could give me... (answered by Alan3354)
Find the value of cot(cos^-1... (answered by jsmallt9)
How do I find the trigonometric function and the requested value? 1. Write the... (answered by lwsshak3)
How do I find the trigonometric function and the requested value? 1. Write the... (answered by stanbon)