SOLUTION: Find the cos 0 (theta) if csc 0(theta) = 11 square root of 2 divided by 12. (I don't have the symbols on my computer to write this exactly like on the page, but it is 11 by square

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Question 171334: Find the cos 0 (theta) if csc 0(theta) = 11 square root of 2 divided by 12. (I don't have the symbols on my computer to write this exactly like on the page, but it is 11 by square root of two, over 12).
Answer by stanbon(57307) About Me  (Show Source):
You can put this solution on YOUR website!
Find the cos (theta) if csc theta) = 11 square root of 2 divided by 12
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General Form: csc(theta) = r/y
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Your Problem:
csc(theta) = [11sqrt(2)]/12 , so r = 11sqrt(2) and y = 12
Find x: x = sqrt(r^2-y^2) = sqrt[121*2 + 144] = sqrt(386)
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Since cos(theta) = x/r, cos(theta) = sqrt(386)/11sqrt(2) = sqrt(193)/11
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Cheers,
Stan H.