SOLUTION: Solve each equation for x in the interval 0≤x ≤2 π:
1/1+tan²x=-cosx
Algebra.Com
Question 170928: Solve each equation for x in the interval 0≤x ≤2 π:
1/1+tan²x=-cosx
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Solve each equation for x in the interval 0≤x ≤2 π:
1/(1+tan²x) = -cosx
-----------------
Since sin^2 + cos^2 = 1
dividing by cos^2 you get
tan^2 + 1 = sec^2
----------------------
So your problem becomes
1/sec^2 = -cosx
cos^2 + cos = 0
cos(cos+1) = 0
cosx = 0 or cosx = -1
x = pi/2 or x = pi
=====================
Cheers,
Stan H.
RELATED QUESTIONS
I have to solve 3cosx = cosx -1 in the interval... (answered by lwsshak3)
Solve for x in the equation (1 +sinx/cosx)+(cosx/1+sinx)=4 for 0≤ x ≤ 2π (answered by HyperBrain)
Solve the following equation for x in the interval 0 ≤ x ≤ 2π
tan(x)... (answered by Edwin McCravy)
Solve the equation algebraically for "x" where 0≤x<2π.
sinx + cosx = 1... (answered by Fombitz)
Solve the equation for x in the interval 0≤x ≤2 π:
2sin²x-sinx-1=0
(answered by stanbon)
Solve the equation algebraically for "x" where 0≤x<2π.
sin2x=cosx
Thank... (answered by Fombitz)
Determine the solutions to the equation tan2x(1-tan^(2)x) = 2/√3 for 0 ≤ x... (answered by ikleyn)
Solve the cos x-1 =0 on the interval 0≤x≤pi/2
x+ π/3
x=0
x=π/6... (answered by richard1234)
question 1
Solve the equation 2 cos2 x + cos x − 1 = 0, 0 ≤ x ≤... (answered by lwsshak3)