SOLUTION: Solve the equation for x in the interval 0≤x ≤2 π: 2sin²x-sinx-1=0

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Question 170922: Solve the equation for x in the interval 0≤x ≤2 π:
2sin²x-sinx-1=0

Answer by stanbon(48558) About Me  (Show Source):
You can put this solution on YOUR website!
Solve the equation for x in the interval 0≤x ≤2 π:
2sin²x-sinx-1=0
Factor to get:
(2sinx+1)(sinx-1) = 0
sinx = -1/2 or sinx = 1
x = (11/6)pi or (7/6)pi or pi/4 or (3/4)pi
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Cheers,
Stan H.