Stanbon's solution is correct but he does not do problem 2 and he does not explain why we know to take the positive square root in 1.
Edwin's solution:
1) If is an angle in quadrant 4 and , find the value of .
Since this involves drawing a graph in which represents
the horizontal axis, not an angle, I will temporarily change
to to avoid a conflict of letters. Change
the problem to read this way:
1) If is an angle in quadrant 4 and , find the value of .
We must use the identity:
However we do not know
So we must first draw the picture of the angle :
We know that is by definition , we
can draw the angle in the 4th quadrant with referent angle
is inside a triangle whose horizontal side is taken
to be the numerator of , considered positive because
it goes right of the y-axis, and whose vertical side is taken as
the denominator , taken negative because it goes down
below the x-axis:
Next we calculate by the Pythagorean theorem:
So we label the slanted line segment .
Now we can find
So we substitute for in
±
Next we must decide whether this is positive or negative:
Since is is the 4th quadrant, then
° so multiplying that through by
°
The means is in quadrant 2. Since
the sine is positive in the 2nd quadrant, the final answer
is
And of course now that we have the answer we can change
back to :
2) What is the solution set of the equation
= in the interval ?
Use the identity to replace on the
left side:
=
=
=
=
=
Now use identity to
replace
=
Factor out
=
Use the zero-factor principle:
3) Find the solution set of over the domain °.
Use identity
Multiply through by
Use the zero-factor principle:
Edwin