SOLUTION: I have no clue where to begin. Please help i'm desperate.
sin(5pi/2)=sin 2 ( ) were using course compass so theirs no textbook
Algebra.Com
Question 168912: I have no clue where to begin. Please help i'm desperate.
sin(5pi/2)=sin 2 ( ) were using course compass so theirs no textbook
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Something is missing from our posting.
Cheers,
Stan H.
RELATED QUESTIONS
sin(x)*cos(y)=1/2[sin(x+y) + sin(x-y)] (1)
cos(x)*sin(y)=1/2[sin(x+y) - sin(x-y)] (2)
(answered by jim_thompson5910)
I have no clue even where to begin this!!!... (answered by Jeff Gordon)
factor completely
x^6 - 14x^4 + 49x^2
i have no clue where to even begin please... (answered by josmiceli)
Simplify using trigonometric identities:
a) 4sin2x cos2x
b) (1+cos2x)/2
c)... (answered by stanbon)
Multiply and simplify. SHOW YOUR STEPS.
√5(2√10+√2x)
Please help (answered by Fombitz)
solve and check:
3/y= 1/2 + 1/2y
I have no clue where to begin for this problem,... (answered by woolybear)
Please help with:z=2(cos5pi/6 + I sin 5pi/6)
(answered by Fombitz)
Simplify the lefthandside so that LHS=RHS
2/sin(b) = sin(b)/cos(b)-1 + sin(b)/cos(b)+1
(answered by greenestamps,solver91311,ikleyn)
i have got up to this point sin 42=x/103 but i have no clue where to go from here can you (answered by Alan3354)