SOLUTION: I'm Having hard time solving this homework. Can anyone help? 2. Calculate the points of the tangent of the curve : y = ex(x2 � 8) where and in which the tangent line is hor

Question 168096: I'm Having hard time solving this homework. Can anyone help?

2. Calculate the points of the tangent of the curve : y = ex(x2 � 8) where and in which the tangent line is horizontal

3. Write one of the two tangents to the curve : y = 1 + x� which are parallel to this equation 12x - y = 1.

4. Calculate
I) If f(x) = ex cos x calculate f �(x) et f ��

(ii) Calculate (d99/ dx99) Sin x

5.
Calculate the derivative :
I) y = xe-x�

II) Let say: r(x) = f(g(h(x))) whit h(1) = 2, g(2) = 3, h�(1)= 4, g�(2) = 5, f�(3) = 6. Calculate r�(1).

III) Show that the function : y = Ae-x + Be-x satisfy the equation with differential y�+ 2y�+y = 0

Answer by oscargut(2103) (Show Source): You can put this solution on YOUR website!
Hi here i answered questions 2) and 3) contact me if you need more help
2. Calculate the points of the tangent of the curve : y = ex(x2 � 8) where and in which the tangent line is horizontal
,
y'=0 if only if x=0
then the point is (0,0) (where the tangent of the curve is horizontal)
3. Write one of the two tangents to the curve : y = 1 + x� which are parallel to this equation 12x - y = 1.

then

then
then 12 (first term of 12x-1 and y'(x)= 3x^2 are the same}
then then or
taking x=2 then equation of the line is where
then line is
Answer:

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