SOLUTION: Hello! My problem is a triangle with a measure of an acute angle A which is 29 degrees, side CA of 18 meters, and a right angle which is angle C. Here's what I found out so far: t

Question 167754This question is from textbook Algebra 1
: Hello! My problem is a triangle with a measure of an acute angle A which is 29 degrees, side CA of 18 meters, and a right angle which is angle C. Here's what I found out so far:
that angle b = 61 degrees
but I do not know how to figure out CB and BA
if you could help, please show step by step instuctions to help me.
Thank You! This question is from textbook Algebra 1

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A which is 29 degrees,
side CA of 18 meters,
and a right angle which is angle C.
---------------------------------------
Here's what I found out so far:
that angle b = 61 degrees
but I do not know how to figure out CB and BA
--------------------
Draw the picture.
CB is opposite angle A=29 degrees.
BA is opposite angle C so BA is the hypotenuse
CA is opposite angle B
----------------------
So, cos(A) = adjacent/hypotenuse
cos(29) = 18/hypotenuse
hypotenuse = 18/cos(29) = 20.58
-----------------------------------
sin(A) = CB/hypotenuse
CB = hypotenuse*sin(A)
CB = 20.58*0.4848..
CB = 9.97738....
==========================
Cheers,
Stan H.
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