SOLUTION: solve:
(sin squared) thetha - sin theta = (cos squared) thetha (for 0 degrees , or equal to thetha < or equal to 2 pi)
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Question 162318: solve:
(sin squared) thetha - sin theta = (cos squared) thetha (for 0 degrees , or equal to thetha < or equal to 2 pi)
Answer by adamchapman(301) (Show Source): You can put this solution on YOUR website!
This one looks like a trig relation to me.
Remember that
.
This will rearrange easily to
.
Put that on the right hand side of the initial equation you gave me:
with our new right hand side:
.
Now we can rearrange to get zero on the right hand side:
.
We treat this like a quadratic equation of the form where x=sin(theta)
The equation factorises to:
.
So
or
keep the sin(theta on the left hand sides of these and rearrange to get
or
=-4.6083,184.6083
and
=0,180,360
convert to radians by multiplying by
Hope this helps,
Adam
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