SOLUTION: Solve:
2sin3theta= square root of 2 (for 0 degress < or equal to thetha < or equal to 360 degrees)
Algebra.Com
Question 162317: Solve:
2sin3theta= square root of 2 (for 0 degress < or equal to thetha < or equal to 360 degrees)
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Solve: 2sin3theta= square root of 2 (for 0 degress < or equal to thetha < or equal to 360 degrees)
---------------
2sin(3theta) = sqrt(2)
sin(3theta) = sqrt(2)/2
3theta = 45º, 135º
theta = 15º, 45º
RELATED QUESTIONS
solve:
(sin squared) thetha - sin theta = (cos squared) thetha (for 0 degrees , or... (answered by adamchapman)
Solve 6cos theta -3 square root 2 =0, for 0 degrees is less than or equal to theta is... (answered by stanbon)
If 0 degrees less than or equal to x less than or equal to 360 degrees, solve the... (answered by ad_alta)
solve secx - square root of 2 = 0 algebraically for all values of x in 0 degrees less... (answered by lwsshak3)
solve for each question for 0 lesser than or equal to theta lesser or equal to 360... (answered by lwsshak3)
solve equation for 0 degrees < or equal to x < or equal to 360 degrees... (answered by lwsshak3)
solve equation for 0 degrees < or equal to x < or equal to 360 degrees
cos2x +... (answered by lwsshak3)
Solve for theta (0 degrees less than or equal to theta<360 degrees)
cos theta=... (answered by tommyt3rd)
solve sin2y = cos4y for y, where 0 degrees < or equal to y <... (answered by josmiceli)