SOLUTION: Solve (triangle) ABC if C=90 degrees, B=20 degrees, and b= 10. Round measures of sides to the nearest tenth and measures of angles to the nearest degree.

Question 149459This question is from textbook Algebra 2
: Solve (triangle) ABC if C=90 degrees, B=20 degrees, and b= 10. Round measures of sides to the nearest tenth and measures of angles to the nearest degree. This question is from textbook Algebra 2

Answer by tryin2bhelpful(6) (Show Source): You can put this solution on YOUR website!
In this equation you can use the law of sines...
a b
__ = __
SinA SinB
you are given both angle B and Side B
From, B=20 and C=90, you can find out what A equals by subracting it from 180
180-20-90= 70... A=70
so...
10 a Cross multiply so you get:
__ = __ 10Sin70=Sin20a so.....
Sin20 Sin70 10Sin70
_______ =a
Sin20
Therefore you'll get 8.476.... or 8.5 rounded=a
Now that you have a, you can find c with a2+b2=c2
(8.5)2+(10)2=c2
172.25=c2

c=13.1 rounded
Now you have all your angles and all of your lengths!!! :)

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