SOLUTION: tan^2x-cot^2x=sec^2x-csc^2x
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Question 148631: tan^2x-cot^2x=sec^2x-csc^2x
Answer by jojo14344(1513) (Show Source): You can put this solution on YOUR website!
Trigo Identities.
We should know that 1+(tan^2x)=sec^2x also 1+(cot^2x)=csc^2x
Substituting these identities to the eqn (tan^2x)-(cot^2x)=(sec^2x)-(csc^2x)
AMP Parsing Error of [(sec^2x)-1-(csc^2-1)=(sec^2x)-(csc^2x)]: Invalid function '\x)-1-(csc^2-1)=(sec^2\x)-(csc^2\x)': opening bracket expected at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 70.
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AMP Parsing Error of [sec^2x-cross(1)-csc^2x+cross(1)=sec^2x-csc^2x]: Invalid function '\x-cross(1)-csc^2\x+cross(1)=sec^2\x-csc^2\x': opening bracket expected at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 70.
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AMP Parsing Error of [sec^2x-csc^2x=sec^2x-csc^2x]: Invalid function '\x-csc^2\x=sec^2\x-csc^2\x': opening bracket expected at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 70.
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----------> Identical
Thank you,
Jojo
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