SOLUTION: I am in desperate need of assistance with an application problem. Any help would be appreciated. The problem: A man at ground level measures the angle of elevation to the top of

Question 143742: I am in desperate need of assistance with an application problem. Any help would be appreciated.
The problem:
A man at ground level measures the angle of elevation to the top of a building to be 53 degrees . If, at this point, he is 12 feet from the building, what is the height of the building? I need find the solution to the nearest hundredths and draw the picture. The same man now stands atop a building. He measures the angle of elevation to the building across the street to be 20 degrees and the angle of depression (to the base of the building) to be 35 degrees. If the two buildings are 50 feet apart, how tall is the taller building? Round to the nearest hundredths.

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A man at ground level measures the angle of elevation to the top of a building to be 53 degrees . If, at this point, he is 12 feet from the building, what is the height of the building? I need find the solution to the nearest hundredths and draw the picture.
:
Draw a right triangle, Let x = the height of the building, then 12 ft from the base of the building to where the man stands and the hypotenuse is from that
point to the top of the building.
:
We can find the height of the building by using the tangent of 53 degrees
Tan =
Tan(53) =
1.327045 =
x = 12 * 1.327045
:
x = 15.9245 ~ 15.92 ft
:
:
The same man now stands atop a building. He measures the angle of elevation to the building across the street to be 20 degrees and the angle of depression (to the base of the building) to be 35 degrees. If the two buildings are 50 feet apart, how tall is the taller building? Round to the nearest hundredths.
:
Draw this out and see that you have two right triangles with a common side of 50'
Find the
tan(20) =
.36397 =
x1 = .36397 * 50
x1 = 18.20 ft
and
tan(35) =
.7002 =
x2 = .7002 * 50
x2 = 35.01 ft
:
Add these two values:
18.20 + 35.01 = 53.21 ft is the height of the building

RELATED QUESTIONS
I need help setting up the following word problem. NOT LOOKING FOR THE ANSWER LOOKING... (answered by Masaries7,ankor@dixie-net.com)

I really need help solving the following problem. Any assistance you can provide me with... (answered by jim_thompson5910)

Please help! I need assistance with this college level challenge problem! I worked out... (answered by Alan3354)

I am attempting to solve a distance problem. But, am finding that I am having difficulty... (answered by ankor@dixie-net.com)

I need assistance with a problem concerning piecewise functions. I am asked to graph the (answered by tommyt3rd)

Find an application for your chosen field--- which is psychology or really anything-- or (answered by ankor@dixie-net.com)

I need help with this word problem, any help would be greatly appreciated. The area of (answered by SHUgrad05)

Hello, I am really confused about this word problem. Setting up the problem properly is... (answered by ankor@dixie-net.com)

I really need someone's help solving the following problem. Any assistance you can... (answered by jim_thompson5910)