# SOLUTION: Write the equation 2x^2-16x-y+24=0 in vertex form. Find the.. (a) vertex (b) axis of symmetry (c) focus (d) directrix oft the parabola thank you.

Algebra ->  Algebra  -> Trigonometry-basics -> SOLUTION: Write the equation 2x^2-16x-y+24=0 in vertex form. Find the.. (a) vertex (b) axis of symmetry (c) focus (d) directrix oft the parabola thank you.      Log On

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 Algebra: Trigonometry Solvers Lessons Answers archive Quiz In Depth

 Question 143412: Write the equation 2x^2-16x-y+24=0 in vertex form. Find the.. (a) vertex (b) axis of symmetry (c) focus (d) directrix oft the parabola thank you.Answer by stanbon(57284)   (Show Source): You can put this solution on YOUR website!Write the equation 2x^2-16x-y+24=0 in vertex form. Find the.. (a) vertex (b) axis of symmetry (c) focus (d) directrix oft the parabola ------------------------------ 2x^2-16x-y+24=0 2x^2-16x = y-24 2(x^2-8x+16) = y-24+2*16 2(x-4)^2 = y + 8 (x-4)^2 = (1/2)(y+8) --------------------- (a) vertex:.................. (4,-8) (b) axis of symmetry:........ x = 4 (c) focus.................... 4p = 1/2 ; p = 1/8 So, focus is (4,-8+(1/8)) or (4,-63/8) (d) directrix of the parabola.. y = -8-(1/8) = -65/8 ============================================= Cheers, Stan H.