SOLUTION: Find all values of x in the interval 0 degrees is less than or equal to x which is less than 360 degrees that satisfy the equation 3cosx+sin2x=0.

Question 143029: Find all values of x in the interval 0 degrees is less than or equal to x which is less than 360 degrees that satisfy the equation 3cosx+sin2x=0.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find all values of x in the interval 0 degrees is less than or equal to x which is less than 360 degrees that satisfy the equation 3cosx+sin2x=0.
-----------------
3cosx + sin2x = 0
3cosx + 2sinxcosx = 0
Factor:
cosx[3 + 2sinx] = 0
cosx = 0 or sinx = -3/2
Solutions in 0 <= x <= 360
If cos=0, x = 0 or 270
--------
sinx cannot equal -3/2
----------
Cheers,
Stan H.

RELATED QUESTIONS
In the interval 0 degrees is less than or equal to x which is less than or equal to 360... (answered by lwsshak3)

Find all values of x in the interval 0 degreesis less than or equal to x wich is less... (answered by jsmallt9)

What are the values of theta in the interval 0 degrees is less than or equal to theta... (answered by lwsshak3)

(cos^2(x)=-cos(x) solve for all values of x in the interval 0 degrees is less than or... (answered by solver91311)

To the nearest ten minutes, find all values of x in the interval 0 (less than or equal... (answered by Alan3354)

To the nearest ten minutes, find all values of x in the interval 0 less than or equal to... (answered by Alan3354)

find all values of x when x is greater than or equal to 0 degrees and less than 360... (answered by solver91311)

find all values of x when x is greater than or equal to 0 degrees and less than 360... (answered by lwsshak3)

Find to the nearest degree all values of theta in the interval 0 degrees is less than or... (answered by stanbon)