SOLUTION: Triangle ABC has side lengths AB = 8, BC = 10, and AC = 12. Find \dfrac{\cos A}{\cos B}.
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Question 1210259: Triangle ABC has side lengths AB = 8, BC = 10, and AC = 12. Find \dfrac{\cos A}{\cos B}.
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52933) (Show Source): You can put this solution on YOUR website!
Answer by greenestamps(13216) (Show Source): You can put this solution on YOUR website!
This triangle is NOT a scale model of a 3-4-5 right triangle....
Use the law of cosines to find cos(A) and cos(B):
Angle A...
Angle B...
ANSWER: 9/2 or 4.5
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