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A minimum value of a sinusoidal function is at (𝜋/4, 3). The nearest maximum value to the
right of this point is at (7𝜋/12, 7). Determine an equation of this function. Please how all your wonderous work.
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This sinusoidal function is between 3 and 7 on vertical axis, so the midline is
y= = 5 and the amplitude is 2 units.
The smallest distance between the minimum and the maximum is
- = - = = = .
along the horizontal axis. Hence, the period T is twice this value, i.e. T = .
Having the minimum at ((𝜋/4, 3), we can use negative cosine with the argument centered at 𝜋/4
y = = .
Solved.
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Post-solution note
Never pack more than one problem per post.
The rules of this forum (and the common sense) do not recommend make it.
Posting more than one problem per post, you work against your own interests.
No one forum for Math help does allow packing more than one problem per post
(which should be as clear as 2 x 2 = 4 to any homo sapiens).