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Solve cos^2(a) + cos(a) = sin^2(a) on the interval 0° ≤ a < 360°.
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Replace sin^2(a) by 1 - cos^2(a).
You will get then
cos^2(a) + cos(a) = 1-cos^2(a),
or
2cos^2(a) + cos(a) - 1 = 0.
It is a quadratic equation relative to cos(a), so you can write the solution
for cos(a) using the quadratic formula
cos(a) = = = .
One root is cos(a) = = = .
It provides the solutions a = 60° and a = 300° in the given interval.
Other root is cos(a) = = -1.
It provides the solution a = 180°.
ANSQER. The solutions to the given equation are the angles 60°, 180° and 300° in ascending order, in the given interval.
Solved.