SOLUTION: Find the general solutions (in radians) of the following equations: (a) 3 cot (3ð‘¥ +ðœ‹/4) = √3 (b) cos(4ð‘¥) − 3 sin (3ðœ‹/2+ 2ð‘¥) + 2 = 0

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Question 1204329: Find the general solutions (in radians) of the following equations:
(a) 3 cot (3ð‘¥ +ðœ‹/4) = √3
(b) cos(4ð‘¥) − 3 sin (3ðœ‹/2+ 2ð‘¥) + 2 = 0

Answer by ikleyn(52931)   (Show Source): You can put this solution on YOUR website!
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Find the general solutions (in radians) of the following equations:
(a) 3 cot (3ð‘¥ +ðœ‹/4) = √3
(b) cos(4ð‘¥) − 3 sin (3ðœ‹/2+ 2ð‘¥) + 2 = 0
~~~~~~~~~~~~~~~~~~~~~~~~~~


        In this my post I will solve part  (a),  ONLY.


     = 

implies

     = 

     = 

     = 

     =  + ,  k = 0, +/-1, +/-2, . . . 


     =  + 

     =  + 

    x =  + ,   k = 0, +/-1, +/-2, . . . 


It is the general solution, in radians.

Solved.

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