A and B are the two points from which the given angles of elevation are measured. G is the base of the tree, and T is the top of the tree. x is the distance from A to the base of the tree G. Using right triangle ATG, Using right triangle BTG, So the system to solve is which the other tutor gave. Solving is easier if you let and Cross multiply: Solve the 2nd equation for x Substitute that for x in the 1st equation: Multiply through by u Get the y terms on the left: Factor out y: Substituting tan(38o) for u and tan(22o) for v Edwin
. As ∡CAD = 38o, ∡CAB = 180 - 38 = 142o In ΔABC, ∡BCA = 180 - (142 + 22), or 38 - 22 = 16o Use Law of Sines to find AC, as follows:
AC * sin 16o = 46 * sin 22o ------ Cross-multiplying Continue solving for AC We then have: Since AC is already known (from above), you need to CONTINUE onward and solve for CD, the height of the tree. When done, you should get a height of approximately 38.49115544, which when rounded to 1 decimal place, is about 38.5'(CHOICE E.).