SOLUTION: Dear tutor, How do I solve these trig equtions? I did not see a similar example on the suggested equitions here. Q1. 2cos(π/4x)+√3 =0 Q2. 4sin(π/4(x+2))+2 =0 Thank

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Question 1196768: Dear tutor,
How do I solve these trig equtions? I did not see a similar example on the suggested equitions here.
Q1. 2cos(π/4x)+√3 =0
Q2. 4sin(π/4(x+2))+2 =0
Thank you so much.
Found 2 solutions by MathLover1, ewatrrr:
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

Q1.






general solutions:
, element
, element

Q2.









general solutions:
, element
, element

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi
 Q1. 2cos(π/4x)+√3 =0 
0r cos(π/4x) = -√3/2 
  | See wheel below (cosx, sinx)  
   cos(5π/6) = -√3/2   
          |Cross multiply and solve for x
      20πx = 6π
         x = 6/20 = 3/10

Q2. 4sin(π/4(x+2))+2 =0   0r sin (π/4(x+2)) = -2/4 = -1/2 
Look on Wheel:   sin (7π/6) = -1/2
  |Cross multiply and solve for x 
 .
Wish You the Best.


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