SOLUTION: If sin(x) = 1/3 and sec(y) = 13/12, where x and y lie between 0 and 𝜋2, evaluate the expression. cos(x + y)

SOLUTION: If sin(x) = 1/3 and sec(y) = 13/12, where x and y lie between 0 and 𝜋2, evaluate the expression. cos(x + y)

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Question 1196624: If
sin(x) = 1/3 and sec(y) = 13/12,
where x and y lie between 0 and 𝜋2,
evaluate the expression.
cos(x + y)
Answer by ikleyn(52817) (Show Source): You can put this solution on YOUR website!
.

A TWIN problem was just solved at this forum under this link

https://www.algebra.com/algebra/homework/Trigonometry-basics/Trigonometry-basics.faq.question.1196621.html

Use it as your TEMPLATE and solve this current problem in similar way.

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