SOLUTION: If sin(x) = 1/3 and sec(y) = 13/12, where x and y lie between 0 and 𝜋/2, evaluate the expression. sin(x − y)

Question 1196621: If sin(x) = 1/3 and sec(y) = 13/12, where x and y lie between 0 and 𝜋/2,
evaluate the expression.
sin(x − y)

Answer by ikleyn(52865) (Show Source): You can put this solution on YOUR website!
.
If sin(x) = 1/3 and sec(y) = 13/12, where x and y lie between 0 and 𝜋/2,
evaluate the expression sin(x − y).
~~~~~~~~~~~~~~~~~~~

If sin(x) = 1/3 and x lies between 0 and 𝜋/2,  then  

   cos(x) =  =  = .


If sec(y) = 13/12,  then  

   cos(y) =  = 12/13  and  sin(y) =  =  = .


sin(x-y) = sin(x)*cos(y) - cos(x)*sin(y) =  =  = 

         =  = .        ANSWER

Solved.

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