SOLUTION: cos(2\alpha +(\pi )/(4))=3tan(2\alpha +(\pi )/(4))

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Question 1195997: cos(2\alpha +(\pi )/(4))=3tan(2\alpha +(\pi )/(4))
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52800)   (Show Source): You can put this solution on YOUR website!
.

I read this equation in this way

     = .


Notice that the argument under cosine function is the same as under the tangent function.

So, I introduce new variable

    x = .


Then the given equation takes the form

    cos(x) = 3*tan(x).


It implies

    cos^2(x) = 3*sin(x),

    1-sin^2(x) = 3*sin(x)

    sin^2(x) + 3*sin(x) - 1 = 0

It is a quadratic equation relative sin(x).  Use the quadratic formula

    sin(x) =  = .


Since sin(x) must be between -1 and 1, only the root sin(x) =  = 0.30278  really fits.


Hence,  there are two solutions for x:

    x = arcsin(0.30278) = 0.3076  OR  x =  = 3.14159 - 0.3076 = 2.834 (rounded).


It gives two solutions for :

    (a)   =  =  = -0.2389  (rounded);

    (b)   =   =   =  1.0243  (rounded).

Solved.



Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!


(1) Note your post contains no question....

No matter how obvious it is what your question is, the polite thing to do in your post is ask the question.

(2) There is no standard use of the "\" symbol, so I don't know what to make of "(2\alpha +(\pi )/(4))"....

But the equation is of the form , which can be solved for x:







That does not factor over the integers, so use the quadratic formula.


The other root produces an invalid value for sin(x), so it can be ignored.

But, since I have no idea what your post means, I don't know if that is of any help to you....


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