SOLUTION: please help me solve sin(2cos^-1(2v))

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Question 1194932: please help me solve sin(2cos^-1(2v))
Answer by ikleyn(52873)   (Show Source): You can put this solution on YOUR website!
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please help me solve sin(2cos^-1(2v))
~~~~~~~~~~~~~~~~~

They want you find sin(2a), given that cos(a) = 2v  and  0 <= a < .


Apply the formula for the sine of  doubled argument

    sin(2a) = 2sin(a)*cos(a).


In this formula, you are just given that cos(a) = 2v; but you still don't know sin(a).


You can easy find the expression for sin(a): it is

    sin(a) =  =  = .



             Notice here, that I use the positive square root for sine, 
             since the sine function is positive for 0 <= a < .


THEREFORE, 

    sin(2cos^-1(2v)) = 2*sin(a)*cos(a) =  = .


ANSWER.  sin(2cos^-1(2v)) = .

Solved.

--------------

I know that for many students,  the entire formulation of such problems is often non-understandable,
as well as it is non-understandable thing where and how to start.


        Try to start using the words  " They want you find . . . ",  as  I  started my solution.

        It may happen  that your internal voice will give then a que to you on how to continue.


For such problems,  these words  " They want you find . . . "  are magic words  (like a mantra)
and often help to start and to solve the problem to the end.

---------------

To see other similar solved problems on calculating trig functions,  look into the lessons
    - Calculating trigonometric functions of angles
    - Advanced problems on calculating trigonometric functions of angles
in this site.

Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic  "Trigonometry: Solved problems".


Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.




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