SOLUTION: A building is 50 feet high. At a distance away from the building, an observer notices that the angle of elevation to the top of the building is 41º. How far is the observer fro

Question 1194209: A building is 50 feet high. At a distance away from the building, an observer notices that the angle of elevation to the top of the building is 41º.
How far is the observer from the base of the building?
A.57.52 ft.
B.34.40 ft
C.43.46 ft.
D.48.86 ft.
Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website!
.
A building is 50 feet high. At a distance away from the building, an observer notices that
the angle of elevation to the top of the building is 41º.
How far is the observer from the base of the building?
A.57.52 ft.
B.34.40 ft
C.43.46 ft.
D.48.86 ft.
~~~~~~~~~~~~~~~~~

Recall the definition of the tangent function and write

    tan(41°) = ,


where x is the distance under the problem's question.


From this equation, find   x =  =  = 57.52 ft.    ANSWER

Solved.

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