SOLUTION: Solve: sec^2x + tan^2x=7

Question 1189409: Solve: sec^2x + tan^2x=7
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Solve: sec^2x + tan^2x=7
-----
1/cos^2 + sin^2/cos^2 = 7
1 + sin^2 = 7cos^2 = 7(1- sin^2) = 7 - 7sin^2
8sin^2 = 6
sin^2 = 3/4
sin(x) = sqrt(3)/2
x = pi/3, 2pi/3 + n*2pi (n is an integer)
----------------
sin(x) = -sqrt(3)/2
x = 4pi/3, 5pi/3 + n*2pi
RELATED QUESTIONS
sec^4x � sec^2x = tan^4x +... (answered by Alan3354)

solve tan 2x + sec 2x = 7 over the interval... (answered by Alan3354,greenestamps)

1) (1+tan^2x)/(1-tan^2x) = sec... (answered by swincher4391)

tan^2x+6=sec^2x+5 (answered by MathLover1)

simplify... (answered by fractalier)

Simplify -tan^2x-1/sec^2x My work: -sec^2x/sec^2x =... (answered by Alan3354)

tan^2x-cot^2x=sec^2x-csc^2x (answered by jojo14344)

(tanx + cot x) * tan x =... (answered by nyc_function)

solve tan 2x + sec 2x = 6 over the interval [0,... (answered by MathLover1)