SOLUTION: Solve the equation 12sin^3x-20sin^2x+sinx+3=0 given that 2sinx-1 is one factor and x is in between 0 and 360 degrees.
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Question 1186338: Solve the equation 12sin^3x-20sin^2x+sinx+3=0 given that 2sinx-1 is one factor and x is in between 0 and 360 degrees.
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
Let y = sinx.
===> The equation can be represented as . From the hint, 2y - 1 is a factor of the left-hand side.
===> after dividing both sides by 2y - 1.
===> (3y + 1)(2y - 3) = 0 ===> y = -1/3 or 3/2.
Since y = sinx = 3/2 has no solution, we solve y = sinx = -1/3.
===> x = , (both in degrees).
Finally the solutions for 2sinx - 1 = 0, or sinx = 1/2, are x = , (both in degrees).
All the values in red ink are the solutions to the original equation.
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