SOLUTION: {{{If arcSin(x) + arcSin(y) + arcSin(z)}}} = 3pi/2}}} then find value of x^9 + y^9 + z^9 - (1/x.y.z)^9 where / means division and ^9 means power 9.

Question 1184167: = 3pi/2}}} then find value of x^9 + y^9 + z^9 - (1/x.y.z)^9 where / means division and ^9 means power 9.
Answer by ikleyn(52814) (Show Source): You can put this solution on YOUR website!
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If arcsin(x) + arcsin(y) + arcsin(z) = then find value of x^9 + y^9 + z^9 - (1/x.y.z)^9 where / means division and ^9 means power 9.
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Function  arcsin()  has the range from    to  .


Therefore, if  arcsin(x) + arcsin(y) + arcsin(z) = ,  then it implies

    arcsin(x) = arcsin(y) = arcsin(z) = .


Hence,

    x = y = z =  = 1.


Therefore,

    x^9 + y^9 + z^9 -  = 1 + 1 + 1 - 1 = 2.


ANSWER.  If  arcsin(x) + arcsin(y) + arcsin(z) =   then  x^9 + y^9 + z^9 -  = 2.

Solved.

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