SOLUTION: Evaluate cos(πΌ + π½) given sin(πΌ) = 5/6, πΌ ππ ππΌπΌ and tan(π½) = 1/2, π½ ππ ππΌπΌπΌ
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Question 1181851: Evaluate cos(πΌ + π½) given sin(πΌ) = 5/6, πΌ ππ ππΌπΌ and tan(π½) = 1/2, π½ ππ ππΌπΌπΌ
Answer by math_tutor2020(3817) (Show Source): You can put this solution on YOUR website!
I'll use A and B in place of πΌ and π½
If sin(A) = 5/6, then cos(A) = -sqrt(11)/6. You can use the pythagorean trig identity cos^2+sin^2 = 1 to see why this works. Or you can draw out a right triangle to find the missing side (using the pythagorean theorem). So it's not a coincidence that the term 'pythagorean' comes up with this trig identity.
Note: cosine is negative in Q2
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If tan(B) = 1/2, then we have an opposite side of 1 and adjacent side of 2.
This leads to a hypotenuse sqrt(1^2+2^2) = sqrt(5), which is again where the pythagorean theorem comes up.
Through a bit of algebra, you should find these two facts:
sin(B) = -sqrt(5)/5
cos(B) = -2sqrt(5)/5
Both sine and cosine are negative in Q3
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In the previous two sections, we found the following four facts
cos(A) = -sqrt(11)/6
cos(B) = -2sqrt(5)/5
sin(A) = 5/6
sin(B) = -sqrt(5)/5
Use those four items in the identity below
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