SOLUTION: Solve for the value of y link- https://docs.google.com/document/d/1hf8uwIw8fFnsNvDRnb9Zj-9iotF3XSFF1I16o44rGfw/edit?usp=sharing can someone please solve the problem I am stu

Algebra.Com
Question 1181736: Solve for the value of y
link- https://docs.google.com/document/d/1hf8uwIw8fFnsNvDRnb9Zj-9iotF3XSFF1I16o44rGfw/edit?usp=sharing
can someone please solve the problem I am stuck

Found 2 solutions by Solver92311, MathTherapy:
Answer by Solver92311(821)   (Show Source): You can put this solution on YOUR website!


Use the Law of Sines.



to calculate Angle Z.

Where is the side opposite angle , and so on.

Then use the fact that the sum of the interior angles of any triangle is 180 degrees to find angle .

Then use the Law of Sines again to find the measure of side

John

My calculator said it, I believe it, that settles it

From
I > Ø

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

Solve for the value of y
link- https://docs.google.com/document/d/1hf8uwIw8fFnsNvDRnb9Zj-9iotF3XSFF1I16o44rGfw/edit?usp=sharing
can someone please solve the problem I am stuck
Find ∡Z first, by using the LAW of SINES, as follows:  
------ Cross-multiplying



That makes ∡Y, 180 - (110 + 24.49) = 180 - 134.49 = 45.51o
Now, you can find y by applying the Law of Sines once again. This is:
Follow the same concept shown earlier, to solve for side y, or side XZ.
RELATED QUESTIONS

Solve for the value of p. solve for the values of y and 2. link-... (answered by Solver92311)
Solve for the value of b. photo link -... (answered by Boreal)
Solve XYZ photo link-... (answered by greenestamps,ikleyn)
State the sidelength of AC and AB. Please view link for diagram.... (answered by josgarithmetic)
State the sidelength of AC and AB. Please view link for diagram.... (answered by greenestamps)
Find the length of AC.... (answered by ikleyn)
Find the length of AC.... (answered by greenestamps,Solver92311)
https://docs.google.com/document/d/1fwlRpNqz5l4Gbc2NvkH3RhcdsyxG3drAzyvOFfMwz48/edit?usp=s (answered by Theo)
photo link-... (answered by Edwin McCravy)