SOLUTION: Solve sin3x = cos3x for 0° < x < 360°. In terms of decimals.

Question 1180390: Solve sin3x = cos3x for 0° < x < 360°. In terms of decimals.
Answer by ikleyn(52797) (Show Source): You can put this solution on YOUR website!
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Solve sin3x = cos3x for 0° < x < 360°. .
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If  sin(3x) = cos(3x),  then it implies


    3x = 90° - 3x + k*360°,  or


    3x + 3x = 90° + k*360°

       6x   = 90° + k*360°.


Giving  "k"  the values k= 0, 1, 2, 3, 4, 5, you get 6 (six) values for x in the given interval


     x = 15°, 75°, 135°, 195°, 255°, 315°.      ANSWER

Solved.

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