SOLUTION: Solve the equation, where 0° ≤ x < 360°.
2 sin^2 x = 1 − cos x
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Question 1178161: Solve the equation, where 0° ≤ x < 360°.
2 sin^2 x = 1 − cos x
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
sin^2 x=1-cos^2 x
so 2-2cos^2x=1-cos x
0=2 cos^2 x-cos x -1
0=(2 cos x+1)(cos x-1)
cos x =-0.5
cos x=+1
x=0 degrees, 120 degrees, 240 degrees
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