.
The numerator is
-3 + 4cos^2(x) = -3 + 4*(1-sin^2(x)) = 1 - 4sin^2(x) = (1-2sin(x))*(1+2sin(x)).
Now, =
(after canceling the factor (1-2sin(x)) in the numerator and denominator)
= 1 + 2sin(x).
Therefore, in this identity a= 1, b= 2.
Surely, the identity is valid only over the domain, which is the entire number line excluding the roots of the denominator
1 - 2sin(x) = 0, i.e. except x= arcsin(1/2) = . ANSWER
Solved, answered and explained. And completed.
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This problem was posted to the forum a week or two ago, and I solved it under this link
https://www.algebra.com/algebra/homework/Trigonometry-basics/Trigonometry-basics.faq.question.1177378.html
https://www.algebra.com/algebra/homework/Trigonometry-basics/Trigonometry-basics.faq.question.1177378.html
Here I simply pasted and copied that my solution for your convenience.
E N J O Y (!)