Hi
(−7, −7) 3rd quadrant
r = sqrt(x^2 + y^2) = sqrt(98) = ± 7√2
for the point for 0 ≤ 𝜃 < 2𝜋
tan θ = 1 Look below: θ is 5π/4 (3rd quadrant) 0r 5π/4 - π = π/4 if r< 0
two sets of polar coordinates: (r,θ)
(7√2, 5π/4) and (-7√2, π/4)
Wish You the Best in your Studies
(cos, sin) Unit Circle:
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