SOLUTION: If 0° < A, B < 90°, and sin A = cos B, what is the value of cot (A+B)?
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Question 1175562
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If 0° < A, B < 90°, and sin A = cos B, what is the value of cot (A+B)?
Answer by
ikleyn(52797)
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If 0° < A, B < 90°, and sin A = cos B, then A + B =
. THEREFORE, cot (A+B) =
= 0.
ANSWER
Solved, answered and explained. And completed.
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