SOLUTION: If cot θ=-2/9, cos θ > 0; csc 0. Find the value of the indicated function.

Question 1174584: If cot θ=-2/9, cos θ > 0; csc 0. Find the value of the indicated function.

Found 2 solutions by Abdulfatai Lanre, MathTherapy:
Answer by Abdulfatai Lanre(2) (Show Source): You can put this solution on YOUR website!
Cot𝈚=-2/9.
Recall that cot𝈚=1/tan𝈚
1/tan𝈚=-2/9.
Cross multiplying,we have
9x1=-2tan𝈚
9=-2tan𝈚
9/-2=tan𝈚
-4.5=tan𝈚
tan𝈚=-4.5
𝈚=arctan(4.5)
𝈚=77.45
𝈚 approx. 77.5(1dp)
cos𝈚 > 0.
Cos77. 5 > 0.
O.216 > 0.True

Answer by MathTherapy(10555) (Show Source): You can put this solution on YOUR website!
If cot θ=-2/9, cos θ > 0; csc 0. Find the value of the indicated function.

Follow the same PREMISE used for this problem thatw's used in the problem below:
Trigonometry-basics/1174583

Given that sin θ > 0, and sec/cos θ < 0, 0 is found in Quadrant 2.
We then have:

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