SOLUTION: \cos A=\frac{5}{13}cosA=
13
5
and \sin B=\frac{12}{37}.sinB=
37
12
. Find the value of \cos(A+B)cos(A+B) in simplest form.
Algebra.Com
Question 1173969: \cos A=\frac{5}{13}cosA=
13
5
and \sin B=\frac{12}{37}.sinB=
37
12
. Find the value of \cos(A+B)cos(A+B) in simplest form.
Answer by ikleyn(52834) (Show Source): You can put this solution on YOUR website!
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