SOLUTION: How would I go about finding the area of a triangle with 2 sides and 1 angle given? Eg: one side is 120, the other 200 with an angle of 41 between them. (without using law of cosin

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Question 1172701: How would I go about finding the area of a triangle with 2 sides and 1 angle given? Eg: one side is 120, the other 200 with an angle of 41 between them. (without using law of cosines)
Found 2 solutions by ankor@dixie-net.com, ikleyn:
Answer by ankor@dixie-net.com(22740)   (Show Source): You can put this solution on YOUR website!
How would I go about finding the area of a triangle with 2 sides and 1 angle given? Eg: one side is 120, the other 200 with an angle of 41 between them. (without using law of cosines)
:
We can find the height. A right triangle is formed, using sin(41), hypotenuse = 120 and side opposite is h,
so we have: sin(41) =
h = 78.7271
A = b*h, where b=200 and h=78.73
A = *200*78.7271
A = 7872.7 sq/units
Answer by ikleyn(52817)   (Show Source): You can put this solution on YOUR website!
.

If two sides of a triangle are given as  " a"  and  " b"  with the angle    between them,


then there is a STANDARD FORMULA for the area of the triangle


   area = .


M E M O R I Z E  it  and  use it every time in this situation.


There is NO NEED to derive it every time anew - it is a STANDARD FORMULA for everyday use, which people know and use for thousands years.

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See the lesson
    - Formulas for area of a triangle
in this site.


Do not miss other lessons on this subject  (the area of a triangle)  that you find in the links at the end of that lesson.



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