SOLUTION: Find exact solution to the interval [0, 2x]. 1/sec2x + 2 + sin2x + 4cos2x = 0

SOLUTION: Find exact solution to the interval [0, 2x]. 1/sec2x + 2 + sin2x + 4cos2x = 0

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Question 1172219: Find exact solution to the interval [0, 2x].
1/sec2x + 2 + sin2x + 4cos2x = 0
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find exact solution to the interval [0, 2x].
interval [0,2x] ?
==============================
1/sec2x + 2 + sin2x + 4cos2x = 0
Is is 1/sec(2x)?
Or 1/(sec(2x) + 2) ?
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