SOLUTION: For the following question determine exact solutions where possible. If
exact solutions are not possible determine approximate solutions, rounded
to the nearest hundredth of a ra
Algebra.Com
Question 1169241: For the following question determine exact solutions where possible. If
exact solutions are not possible determine approximate solutions, rounded
to the nearest hundredth of a radian. Show all of your work.
15. Solve 4 tan^2 x + 2 tan x - 3 = 0 on the interval x belongs to [0, 2π].
I am not sure if my answer is correct . I got 0.5 Can somebody help
Rita
Answer by Solver92311(821) (Show Source): You can put this solution on YOUR website!
Let )
, then:
I'll leave it to you to verify that the roots are 
So then \text{ or }\arctan\(\frac{-1\,-\,\sqrt{13}}{4}\))
.
However, )
is outside the domain interval specified for the problem, so to find the values of the angle for the negative root you need: \ +\ \pi)
and \ +\ 2\pi)
.
For the positive root of your quadratic you need: )
and \ +\ \pi)
See the diagram
.
John
My calculator said it, I believe it, that settles it
From
I > Ø
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