SOLUTION: Find all degree solutions in the interval 0° ≤ 𝜃 < 360°. If rounding is necessary, round to the nearest tenth of a degree. Use your graphing calculator to verify the solutio
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Question 1168932: Find all degree solutions in the interval 0° ≤ 𝜃 < 360°. If rounding is necessary, round to the nearest tenth of a degree. Use your graphing calculator to verify the solution graphically. (Enter your answers as a comma-separated list.)
3 sin^2 𝜃 − 7 cos 2𝜃 = 0
Answer by Solver92311(821) (Show Source): You can put this solution on YOUR website!
\ -\ 7\cos(2\theta)\ =\ 0)
\ -\ 7\(\cos^2(\theta)\,-\,\sin^2(\theta)\)\ =\ 0)
\ -\ 7\cos^2(\theta)\ =\ 0)
\ =\ 7\ -\ 7\sin^2(\theta))
\ =\ 7)
\ =\ \frac{7}{11})
\ =\ \pm\sqrt{\frac{7}{11}})
)
Restricting the range of the inverse sine to 
\ +\ 90n\ \forall\ n\ \in\ \{0,1,2,3\})
You can do your own calculator work.
John
My calculator said it, I believe it, that settles it
I > Ø
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