SOLUTION: A student throws a water balloon vertically downward from the top of a 50.0 m tall building.
The balloon leaves the thrower's hand with a speed of 5.55 m/s. Air resistance is ign
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Question 1165049: A student throws a water balloon vertically downward from the top of a 50.0 m tall building.
The balloon leaves the thrower's hand with a speed of 5.55 m/s. Air resistance is ignored.
a. How far does it fall in a time of 1.70 s?
b. What is the velocity of the balloon as it reaches the ground?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Evaluate the height function, \ =\ -4.9t^2\ +\ v_ot\ +\ h_o)
where 
and 
is the height of the building.
\ =\ -4.9(1.70)^2\ -\ 5.55(1.70)\ +\ 50)
This gives you the height at the specified time. As long as this value is less than the height of the building, subtract the height at that time from the height of the building to determine the distance fallen.
Instantaneous velocity is the derivative of the height function evaluated at the time when the height is zero.
Solve the quadratic:
to find the elapsed time when the balloon hits the ground, 
.
\ =\ -4.9t^2\ -\ 5.55t\ +\ 50)
\ =\ -9.8t\ -\ 5.55)
Evaluate the derivative at
John
My calculator said it, I believe it, that settles it
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