SOLUTION: Let cosA=-5/13 with A in Q3 and sinB=3/5 with B in Q1. Find sin(A-B), cos(A-B), and tan(A-B).
All I know how so far is just the formula sin(A-B)=sinAcosB-cosAsinB and cos(A-B)=c
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Question 1162379: Let cosA=-5/13 with A in Q3 and sinB=3/5 with B in Q1. Find sin(A-B), cos(A-B), and tan(A-B).
All I know how so far is just the formula sin(A-B)=sinAcosB-cosAsinB and cos(A-B)=cosAcosB+sinAsinB.
Found 2 solutions by greenestamps, ikleyn:
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
5-12-13 and 3-4-5 are Pythagorean Triples.
Given cosA = -5/12, sinA is 12/13 or -12/13, depending on the quadrant.
Given sinB = 3/5, cosB is 4/5 or -4/5, depending on the quadrant.
After you find sinA and cosB, use the formulas you show to find sin(A-B) and cos(A-B).
Then tan(A-B) is just sin(A-B) divided by cos(A-B).
Answer by ikleyn(52798) (Show Source): You can put this solution on YOUR website!
.
For many similar solved problems (your TEMPLATES) see the lessons
- Calculating trigonometric functions of angles
- Advanced problems on calculating trigonometric functions of angles
- Evaluating trigonometric expressions
in this site.
Learn from there as much as you can (!) (!)
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Trigonometry: Solved problems".
Save the link to this textbook together with its description
Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
into your archive and use when it is needed.
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and \sin B=\frac{12}{37}.sinB=
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(answered by ikleyn)