SOLUTION: Solve by substitution:
y=(5/8)x+4
16y+3x=-40
Algebra.Com
Question 1161840: Solve by substitution:
y=(5/8)x+4
16y+3x=-40
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
y=(5/8)x+4
16y+3x=-40
-----------
Sub for y in the 2nd eqn
=================
Multiply the 1st eqn by 16 to avoid fractions:
16y = 10x + 64
16y + 3x = -40
--
Then sub for 16y in the 2nd eqn
RELATED QUESTIONS
Solve by substitution
x + 3x = 5
-2x + y =... (answered by ewatrrr)
Solve by substitution. y = 4 – 3x and 3x + y = 5 (answered by Alan3354,MathLover1)
Y=3x-4
Y=4+x
Solve by... (answered by mananth)
solve by substitution:
1: x-y=-8
y=3x
2: 2x+y=1
x=8-3y
Solve:
3:x+y=20
-2x+y=5
(answered by Alan3354)
Solve by substitution..
y= -3x+4
-6x-2y=... (answered by Tias_411)
Solve each system by substitution.
y = x - 5
3x - 4(y - 2) = 28 -... (answered by palanisamy)
solve by substitution 3x+y= -3... (answered by stanbon)
Solve each system by substitution
1)y=2x-8
4x+3y=1
2)y=x-5... (answered by Fombitz)
Solve by substitution:
3x + 2y =27
x= y +... (answered by lyra)