SOLUTION: Find sec^-1 ((-2√3)/(3)) exactly in both radians and degrees

Question 1161418: Find sec^-1 ((-2√3)/(3)) exactly in both radians and degrees
Answer by Edwin McCravy(20060) (Show Source): You can put this solution on YOUR website!




If an angle has a secant of

 

then it has a cosine which is its reciprocal

 

We rationalize the denominator:









Angles that have this for their cosine are special angles that
we can find on the unit circle, in QII and QIII:

In degrees they are 150° and 210°

In radians they are 5π/6 and 7π/6

Edwin

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