SOLUTION: Find a root of an equation f(x)=2coshxsinx-1 taking initial value x_0=0.4, using Newton Raphson method correct up to four decimal places.

Question 1160708: Find a root of an equation f(x)=2coshxsinx-1 taking initial value x_0=0.4, using Newton Raphson method correct up to four decimal places.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!


By Newton-Raphson				
				
     x_i	   f(x_i)          f'(x_i)	    x_i - f(x_i)/f'(x_i)
0.4	       -0.158021178	2.311376166	        0.468366707
0.468366707	0.00371148	2.422461324		0.466834596
0.466834596	2.03273E-06	2.419809038		0.466833756
0.466833756	6.09734E-13	2.419807586		0.466833756
0.466833756	0	        2.419807586		0.466833756

John

My calculator said it, I believe it, that settles it

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