SOLUTION: find the exact value between 0 to 2pi.
tan (x/2)=cscx
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Question 1155862: find the exact value between 0 to 2pi.
tan (x/2)=cscx
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
find the exact value between 0 to 2pi.
tan (x/2)=cscx
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Sub u for x/2
---
tan(u) = 1/sin(2u) = 1/(2*sin(u)*cos(u))
sin(u)/cos(u) = 1/(2*sin(u)*cos(u))
sin(u) = 1/(2*sin(u))
2sin(u) = 1/sin(u)
2sin^2(u) = 1
sin^2(u) = 1/2
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