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The general statement is
If cos(a) + cos(b) = 0, then
EITHER a + b = +
OR a - b = + .
If apply it to x and 3x, then
EITHER x + 3x = +
OR |x - 3x| = + .
First case gives
4x = ; hence, x = , or x = , or x = , or x = .
Second case gives
2x = ; hence, x = , or x = .
These 6 listed values are the full set of solutions to the given equation in given interval.
Solved.
Another approach is possible.
Use the general formula
cos(a) + cos(b) = .
When you apply it with x and 3x, you get
cos(x) + cos(3x) = 2*cos(2x)*cos(x) = 0,
which leads you to the SAME answer.
Solved.